Template:liv-noun-sieldõ
Declension of liv-noun-sieldõ
singular (ikšlug) | plural (pǟgiņlug) | |
---|---|---|
nominative (nominatīv) | [[{{{1}}}{{{2}}}#Livonian|{{{1}}}{{{2}}}]] | [[{{{1}}}{{{2}}}d#Livonian|{{{1}}}{{{2}}}d]] |
genitive (genitīv) | [[{{{1}}}{{{2}}}#Livonian|{{{1}}}{{{2}}}]] | [[{{{1}}}{{{2}}}d#Livonian|{{{1}}}{{{2}}}d]] |
partitive (partitīv) | [[{{{1}}}{{{2}}}#Livonian|{{{1}}}{{{2}}}]] | [[{{{1}}}idi#Livonian|{{{1}}}idi]] |
dative (datīv) | [[{{{1}}}{{{2}}}n#Livonian|{{{1}}}{{{2}}}n]] | [[{{{1}}}{{{2}}}dõn#Livonian|{{{1}}}{{{2}}}dõn]] |
instrumental (instrumentāl) | [[{{{1}}}{{{2}}}ks#Livonian|{{{1}}}{{{2}}}ks]] | [[{{{1}}}{{{2}}}dõks#Livonian|{{{1}}}{{{2}}}dõks]] |
illative (illatīv) | [[{{{1}}}{{{2}}}z#Livonian|{{{1}}}{{{2}}}z]] [[{{{1}}}{{{2}}}#Livonian|{{{1}}}{{{2}}}]] |
[[{{{1}}}iž#Livonian|{{{1}}}iž]] |
inessive (inesīv) | [[{{{1}}}{{{2}}}s#Livonian|{{{1}}}{{{2}}}s]] | [[{{{1}}}is#Livonian|{{{1}}}is]] |
elative (elatīv) | [[{{{1}}}{{{2}}}st#Livonian|{{{1}}}{{{2}}}st]] | [[{{{1}}}ist#Livonian|{{{1}}}ist]] |
- The following documentation is located at Template:liv-noun-sieldõ/documentation. [edit]
- Useful links: subpage list • links • redirects • transclusions • errors (parser/module) • sandbox
For types of nouns that end with a vowel and have this vowel in affixes where otherwise an õ would be:
- sieldõ – type 118 in Viitso's table.
- lilla – type 56
- Greek terms that retain an -a ending (e.g., summa) are likely to be of lilla type. (Not program though that is of
{{liv-noun-kim}}
type).
- Greek terms that retain an -a ending (e.g., summa) are likely to be of lilla type. (Not program though that is of
Two params stem + the final õ/a: {{liv-noun-reg|sield|õ}}
Two optional params: type and extra or -width, e.g., {{liv-noun-reg|type=type 140|x=-100}}
- Uncountable – provide sg=1 (shows only singular)
- Pluralia tantum – provide pl=1 (shows only plural)
Palatalized consonant
editTypes
- 121 drūošõ
- 120 aššõ
Due to having š these types take -iz in plural illative instead of -iž, provide parameter iz=1 in this case.